What you are asking are the "roots" of the equation x^{2} = 3x. Remember that the equation that will allow us to get the root/s is the quadratic equation given by ax^{2} + bx + c = 0.

In this case, you need to rewrite the equation from x^{2} = 3x by moving all terms to the left. This will then give you the form *x*^{2} -3x = 0, which will allow us to identify *a, b* and *c *of the quadratic equation.

**a** = 1

**b** = -3

**c** = 0

We now substitute this to the quadratic formula:

x= [−b±√b^{2}−4ac]/2a

Substituting the values will give you this:

x= [−(-3)±√(-3)^{2}−4(1)(0)]/2(1)

x= [3±√9]/2

x= [3±3]/2

__First root:__

x= [3+3]/2 = 6/2 = 3

__Second root:__

x= [3-3]/2 = 0

**Hence, the values of x or the roots of the equation are 3 and 0.**