0 votes

To find the value of (x+6)(x+6) = 256, you first need to simplify the left hand side of the equation:

(x+6)(x+6) = x^{2} +6x +6x + 36 = x^{2} + 12x + 36

Substituting this to the original equation will give you this x^{2} + 12x + 36 = 256, which can further be simplified by moving all terms to the left. Doing that will give you the quadratic form (ax^{2} + b^{2} + c = 0) of the equation:

x^{2} + 12x - 220 = 0

Remember that the roots can be obtained by using the quadratic formula given by:

x = [(-b)±√b^{2}-(4ac)] / 2a where a, b, c are the coefficients of the equation. That is, *a* = 1, *b* = 12 and *c* = -220

Substituting the values will give you:

x = [-(12)±√(12)^{2}-(4*1*-220)] / 2(1)

x = [-12±√144-(-880)] / 2

x = [-12±√1024] / 2

x = [-12±32] / 2

First root now equals to:

x = [-12+32] / 2

**x = 10**

Second root:

x = [-12-32] / 2

**x = -22**

There you have it. **The values of x are 10 and -22.**

0 votes

(x+6)(x+6)=256

take sqr root of each side

x+6=16

x= 16 - 6

x= 10

x+6= -16

x= -16 -6

x= -22

we find two answers x= 10 and x= -22

`

take sqr root of each side

x+6=16

x= 16 - 6

x= 10

x+6= -16

x= -16 -6

x= -22

we find two answers x= 10 and x= -22

`

0 votes

The Value of x in the equation (x+6)(x+6)=256

(x+6)(x+6)=256

X^{2}+6x+6x+36=256

X^{2}+12X+36=256

(X+6)^{2}=256 {(a+b)^{2}=a^{2}+2ab+b^{2}}

X+6=16 (take sqr root)

X=16-6

X=10

Ans: X=10

0 votes

(X+6)(X+6)=256

(X+6)^2=256

(X+6)= 256^(1/2)

X+6=+16

X=22

And

X+6=-16

X=-10

You can also solve by making the quadratic equation and solve for that equation.

Any square root have a two solution

(X+6)^2=256

(X+6)= 256^(1/2)

X+6=+16

X=22

And

X+6=-16

X=-10

You can also solve by making the quadratic equation and solve for that equation.

Any square root have a two solution

0 votes

let assume t = x+6

(x+6)(x+6) = 256 => t*t = 256

t^{2} = 256^{ }

^{ t = + or - 16}

^{x + 6 = +16 => x = 10 and x + 6 = -16 => x = -22}

x have two values +10 and -22

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