How to find the value of X in the equation (x+6)(x+6)=256?

replied by LEGEND (7,490 points) 4 15 39

Solving for X in this equation would be as follows:

1. Move all terms to the left side and set equal to zero.
2. Now set each factor equal to zero.

x = 10,-22

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answered by ELITE (3,032 points) 5 21 40

To find the value of (x+6)(x+6) = 256, you first need to simplify the left hand side of the equation:

(x+6)(x+6) = x2 +6x +6x + 36 = x2 + 12x + 36

Substituting this to the original equation will give you this x2 + 12x + 36 = 256, which can further be simplified by moving all terms to the left. Doing that will give you the quadratic form (ax2 + b2 + c = 0) of the equation:

x2 + 12x - 220 = 0

Remember that the roots can be obtained by using the quadratic formula given by:

x = [(-b)±√b2-(4ac)] / 2a where a, b, c are the coefficients of the equation. That is, a = 1, b = 12 and c = -220

Substituting the values will give you:

x = [-(12)±√(12)2-(4*1*-220)] / 2(1)

x = [-12±√144-(-880)] / 2

x = [-12±√1024] / 2

x = [-12±32] / 2

First root now equals to:
x = [-12+32] / 2
x = 10

Second root:
x = [-12-32] / 2
x = -22

There you have it. The values of x are 10 and -22.

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(x+6)(x+6)=256

take sqr root of each side

x+6=16

x= 16 - 6

x= 10

x+6= -16

x=  -16 -6

x= -22

we find two answers x= 10  and  x= -22

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answered by (116 points) 7

The Value of x in the equation (x+6)(x+6)=256

(x+6)(x+6)=256

X2+6x+6x+36=256

X2+12X+36=256

(X+6)2=256 {(a+b)2=a2+2ab+b2}

X+6=16 (take sqr root)

X=16-6

X=10

Ans: X=10

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answered by (137 points) 1 4
(X+6)(X+6)=256

(X+6)^2=256

(X+6)= 256^(1/2)

X+6=+16

X=22

And

X+6=-16

X=-10

You can also solve by making the quadratic equation and solve for that equation.
Any square root have a two solution

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