asked in Mathematics+IQ challenge by (5 points) 4
replied by LEGEND (7,489 points) 4 15 39

Solving for X in this equation would be as follows:

  1. Move all terms to the left side and set equal to zero.
  2. Now set each factor equal to zero.
Your answer:

x = 10,-22

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1 Answer

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answered by ELITE (3,033 points) 5 20 40

To find the value of (x+6)(x+6) = 256, you first need to simplify the left hand side of the equation:

(x+6)(x+6) = x2 +6x +6x + 36 = x2 + 12x + 36

Substituting this to the original equation will give you this x2 + 12x + 36 = 256, which can further be simplified by moving all terms to the left. Doing that will give you the quadratic form (ax2 + b2 + c = 0) of the equation:

x2 + 12x - 220 = 0

Remember that the roots can be obtained by using the quadratic formula given by:

x = [(-b)±√b2-(4ac)] / 2a where a, b, c are the coefficients of the equation. That is, a = 1, b = 12 and c = -220

Substituting the values will give you:

x = [-(12)±√(12)2-(4*1*-220)] / 2(1)

x = [-12±√144-(-880)] / 2

x = [-12±√1024] / 2

x = [-12±32] / 2

First root now equals to:
x = [-12+32] / 2
x = 10

Second root:
x = [-12-32] / 2
x = -22

There you have it. The values of x are 10 and -22.

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