I'm happy to assist you with that.
There are eight possible outcomes when three coins are tossed:
HHH HHT THH TTH THT THT HTT TTT
Three heads-up coins are represented as HHH, two heads and one tail by HHT, and so on.
There are three events that can occur if you receive exactly two tails:
HTH HTH THH
The ratio of successful outcomes to total outcomes determines the likelihood of receiving exactly two tails. The chance in this situation is 3/8 since there are 3 successful outcomes and 8 total outcomes.
Alternatively, you might use the probability formula to resolve this issue:
Probability is calculated as (Number of successful outcomes)/(Number of total outcomes).
P(exactly two tails)=(3)/(8)=0.375
I
hope this is useful.