Question

What is the solution of the quadratic equation x²-4x-5=0

Answer 1

To solve the quadratic equation x^2 - 4x - 5 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 1, b = -4, and c = -5. Plug these values into the quadratic formula:

x = (-(-4) ± √((-4)² - 4(1)(-5))) / (2(1))

Simplify:

x = (4 ± √(16 + 20)) / 2

x = (4 ± √36) / 2

Now, calculate the two possible solutions:

1. x = (4 + 6) / 2 = 10 / 2 = 5

2. x = (4 - 6) / 2 = -2 / 2 = -1

So, the solutions to the quadratic equation x^2 - 4x - 5 = 0 are x = 5 and x = -1.

Answer 2

To find the solution of the quadratic equation x^2 - 4x - 5 = 0, we can use the quadratic formula. The quadratic formula states that the solutions of a quadratic equation ax^2 + bx + c = 0 are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

For the given equation, a = 1, b = -4, and c = -5. Substituting these values into the quadratic formula, we get:

x = (4 ± √((-4)^2 - 4(1)(-5))) / (2(1))

x = (4 ± √(16 + 20)) / 2

x = (4 ± √36) / 2

x = (4 ± 6) / 2

Simplifying further gives us two solutions:

x = (4 + 6) / 2 = 10 / 2 = 5

x = (4 - 6) / 2 = -2 / 2 = -1

Therefore, the solutions to the quadratic equation x^2 - 4x - 5 = 0 are x = 5 and x = -1.

Answer 3

To find the solutions of the quadratic equation x^2 - 4x - 5 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 1, b = -4, and c = -5. Plug these values into the quadratic formula:

x = (-(-4) ± √((-4)² - 4(1)(-5))) / (2(1))

Simplify the equation:

x = (4 ± √(16 + 20)) / 2

x = (4 ± √36) / 2

Now, calculate the two possible solutions:

1. x = (4 + √36) / 2 = (4 + 6) / 2 = 10 / 2 = 5

2. x = (4 - √36) / 2 = (4 - 6) / 2 = -2 / 2 = -1

So, the solutions to the quadratic equation x^2 - 4x - 5 = 0 are x = 5 and x = -1.

Answer 4

The solutions to the quadratic equation x^2 - 4x - 5 = 0 are x = -1 and x = 5.

The quadratic equation x^2 - 4x - 5 = 0 can be solved using various methods such as factoring, completing the square, or using the quadratic formula. In this case, factoring or using the quadratic formula would yield the solutions x = -1 and x = 5. These are the values of x that satisfy the equation and make it true.

Answer 5

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 1, b = -4, and c = -5. Plug these values into the formula:

x = (-(-4) ± √((-4)² - 4(1)(-5))) / (2(1))

Now, simplify:

x = (4 ± √(16 + 20)) / 2

x = (4 ± √36) / 2

x = (4 ± 6) / 2

Now, consider both the positive and negative square root:

x₁ = (4 + 6) / 2 = 10 / 2 = 5

x₂ = (4 - 6) / 2 = -2 / 2 = -1

So, the solutions to the quadratic equation x^2 - 4x - 5 = 0 are x₁ = 5 and x₂ = -1.

Answer 6

There is no real root. There is imaginary roots. So this question has no real answer. There is no need even thow here is imaginary roots x=5 and x=-1.so that's it.

Answer 7

To solve this use the almighty formular 

x = -b ± √(b² - 4ac)) / 2a 

X= -4(-4)± (-4² - 4(1)(-5)) / 2(1) 

X=4±✓4±✓36/2 

4+6/2   4-2/2 

X= 5 and X = -1

Answer 8

This quadratic equation x² -4x-5=0 can be solved by factoring method. The factor are

 (x-5) and (x+1). To find x, equate x-5 to x=5 and x+1 to x =-1.

 So the solution are 5 and -1.

 

 To check if x=5, then 5²  -4(5) - 5 = 0

                                25 - 20 - 5 = 0

                                        5 - 5  = 0

                                              0 = 0 True

 To check if x=-1 then -1² - 4(-1) - 5 = 0

                                         1   + 4     - 5 = 0

                                                    5  - 5 = 0

                                                          0 = 0