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If n=3, what is the value of 2 the power of 2n+1

10 Answers

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If n=3, then 


2n+1 becomes

=2*3+1

=6+1

=7

 So, 2n+1 is equal to 7


And 22n+1  is equal to


27( from above solution) 

=2*2*2*2*2*2*2

=128

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If n=3 then 2^2n+1 would be equal to 2^(2*3+1)=2^7.By putting the value of n in this equation we get the answer which simplifies to 2^7.
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When n=3, 2^ (2n+1)= 2^(2*3+1)

                                    =2^(6+1)

Which equals to 2^7= 2*2*2*2*2*2*2 and is equal to 128.

Therefore, when n=3, 2^(2n+1)=128
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When n = 3, you can calculate 2^(2n+1) as follows:

2^(2n+1) = 2^(2*3+1) = 2^(6+1) = 2^7

Now, calculate 2^7:

2^7 = 2 * 2 * 2 * 2 * 2 * 2 * 2 = 128

So, when n = 3, 2^(2n+1) is equal to 128
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If n is equal to 3, then you can substitute this value into the expression for 2^(2n+1):

2^(2n+1) = 2^(2*3+1) = 2^(6+1) = 2^7

Now, calculate 2^7:

2^7 = 128

So, when n is 3, 2^(2n+1) equals 128.
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If n is 3, then 2n+1 would be equal to 2(3) + 1 = 7. 

Now we can calculate 2 to the power of 2n+1, which is 2^7.

2^7 = 2 x 2 x 2 x 2 x 2 x 2 x 2 = 128.

Therefore, the value of 2^(2n+1) when n=3 is 128.
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If n = 3, you can calculate 2^(2n+1) as follows:

2^(2n+1) = 2^(2*3+1) = 2^(6+1) = 2^7

Now, calculate 2^7:

2^7 = 2 * 2 * 2 * 2 * 2 * 2 * 2 = 128

So, if n = 3, then 2^(2n+1) is equal to 128.
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If n = 3, then the value of 2^(2n+1) can be calculated as follows:

2^(2n+1) = 2^(2(3)+1) = 2^(6+1) = 2^7 = 128.

Therefore, when n = 3, the value of 2^(2n+1) is 128.
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The value will be 7

N=3

2n+1

Putting n=3

2×3+2

6+1

=7


That's the real answer of this question. No one gonna give you best answer then this.
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Certainly! Let's break down the expression step by step:


1. Given \( n = 3 \).
2. Substitute \( n \) into the expression \( 2^{2n+1} \).
3. \( 2^{2n+1} = 2^{2*3+1} \) because \( n \) is replaced by 3.
4. Simplify the exponent: \( 2^{2*3+1} = 2^{6+1} \).
5. Perform the multiplication inside the exponent: \( 6+1 = 7 \).
6. Now we have \( 2^7 \).
7. Calculate \( 2^7 \), which equals 128.

So, when \( n = 3 \), the value of \( 2^{2n+1} \) is \( 128 \).
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