If x2 = 3x
Then what is x?
X²=3x
Therefore,
X²-3x=0
What you are asking are the "roots" of the equation x2 = 3x. Remember that the equation that will allow us to get the root/s is the quadratic equation given by ax2 + bx + c = 0.
In this case, you need to rewrite the equation from x2 = 3x by moving all terms to the left. This will then give you the form x2 -3x = 0, which will allow us to identify a, b and c of the quadratic equation.
a = 1
b = -3
c = 0
We now substitute this to the quadratic formula:
x= [−b±√b2−4ac]/2a
Substituting the values will give you this:
x= [−(-3)±√(-3)2−4(1)(0)]/2(1)
x= [3±√9]/2
x= [3±3]/2
First root:
x= [3+3]/2 = 6/2 = 3
Second root:
x= [3-3]/2 = 0
Hence, the values of x or the roots of the equation are 3 and 0.
We are given:
x^2 = 3x
If x2= 3x.
To solve for x.
Take the log10 of both sides.
We have
Log10x = log103x
2log10x = log103 + log10x
Collect like terms
We have
2log10x - log10x = log103
log10x = log103
Take inverse log10 of both sides
Therefore x= 3.
Since x2 = 3x is quadratic equation, there should be 2 values for x .
So the other answer is 0.