Let's denote your age as "x" and your brother's age as "y".
According to the problem, we know that you are twice as old as your brother, so we can write the equation: x = 2y.
In 20 years, your age will be x + 20, and your brother's age will be y + 20. The problem also states that in 20 years, you will be 1.5 times your brother's age, so we can write the equation: x + 20 = 1.5(y + 20).
We can now solve the system of equations:
x = 2y (Equation 1)
x + 20 = 1.5(y + 20) (Equation 2)
Substituting Equation 1 into Equation 2, we get:
2y + 20 = 1.5(y + 20)
Expanding the equation, we have:
2y + 20 = 1.5y + 30
Subtracting 1.5y from both sides, we get:
0.5y + 20 = 30
Subtracting 20 from both sides, we have:
0.5y = 10
Dividing by 0.5, we find:
y = 20
Using this value of y in Equation 1, we can determine x:
x = 2y
x = 2 * 20
x = 40
Therefore, you are currently 40 years old, and your brother is 20 years old.