# I am twice as old as my brother, but in 20 years, I will be just 1.5 times his age. How old are we now?

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Challenge your IQ and math abilities by figuring out the current ages of two siblings based on this age-related puzzle.

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How about we refer to your ongoing age as "X" and your sibling's ongoing age "Y." You referenced that you are as of now two times as old as your sibling, so we can compose the condition: X = 2Y In 20 years, you will be X + 20 years of age, and your sibling will be Y + 20 years of age. Around then, you will be 1.5 times your sibling's age, so we can compose another condition: X + 20 = 1.5(Y + 20) Presently, we have an arrangement of two conditions: 1. X = 2Y 2. X + 20 = 1.5(Y + 20) We should settle this arrangement of conditions: From the primary condition, we can communicate X regarding Y: X = 2Y. Substitute this articulation for X into the subsequent condition: 2Y + 20 = 1.5(Y + 20) Presently, address for Y: 2Y + 20 = 1.5Y + 30 0.5Y = 10 Y = 20 Now that we know your sibling's age (Y), we can track down your age (X) utilizing the principal condition: X = 2Y X = 2 * 20 X = 40 Along these lines, you are right now 40 years of age, and your sibling is 20 years of age.
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Let's denote your current age as A and your brother's current age as B.

Given that you are twice as old as your brother:

$A = 2B$

In 20 years, you will be $$A + 20$$ and your brother will be $$B + 20$$, and at that time, you will be 1.5 times his age:

$A + 20 = 1.5 \times (B + 20)$

Now, we can use these equations to find your current age (A) and your brother's current age (B).

First, substitute the expression for A from the first equation into the second equation:

$2B + 20 = 1.5 \times (B + 20)$

Now, solve for B (your brother's current age). Once you have B, you can find A using the first equation.

Let's calculate:

$2B + 20 = 1.5 \times (B + 20)$

$2B + 20 = 1.5B + 30$

$0.5B = 10$

$B = 20$

Now that we know your brother's current age (B is 20), we can find your age (A) using the first equation:

$A = 2 \times B$

$A = 2 \times 20$

$A = 40$

So, your current age is 40, and your brother's current age is 20.
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Let x be your current age and x-2 be your brother's current age. You will be x+20 years old in 20 years, but your brother will be x-2+20 = x+18 years old. Because you will be 1.5 times his age at the time, we may use the following equation:

x+20 = 1.5(x+18)

When we simplify the equation, we get:

0.5x = 20 When we solve for x, we get:

x = 40

As a result, you are now 40 years old, whereas your brother is 38.
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Let e represents the elder brother’s current age

Let y represents the younger brother’s current age

e = 2*y = 2y ……………………….. eqn. (i)

In two years’ time:

The elder brother’s age will become (e+ 2) years old

The younger brother’s age will become (y + 2) years old

Five years ago,

The younger brother was (y - 5 + 2) years old

e + 2 = 4(y-5 +2)

e + 2 = 4y - 20 + 8

e = 4y - 14 ………………………………………. eqn. (ii)

From eqn. (i), e = 2y

Substitute e into eqn. (ii)

2y = 4y - 14

2y - 4y = - 14

-2y = -14

2y = 14

y = 14/2

y = 7 years old now

The younger brother is 7 years old now

The elder brother is 7*2 years old now = 14 years old now.

To check if the answers above are correct:

The younger brother is 7 years old now, in two years’ time he will become 9.

Five years ago, he was (9 - 5) years old = 4 years old

The elder brother is 14 years old now, in two years’ time he will become 16 .

The ratio is 16:4, which is equal to ratio 4 to 1.
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Let's say your brother's age is x, then your age is 2x, after 2 years this is what happens:

2x+2 = 4(x-5)

By solving we get your brother's current age (x) = 11years which makes your current age = 22years
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Let's denote your age as "x" and your brother's age as "y".

According to the problem, we know that you are twice as old as your brother, so we can write the equation: x = 2y.

In 20 years, your age will be x + 20, and your brother's age will be y + 20. The problem also states that in 20 years, you will be 1.5 times your brother's age, so we can write the equation: x + 20 = 1.5(y + 20).

We can now solve the system of equations:

x = 2y (Equation 1)

x + 20 = 1.5(y + 20) (Equation 2)

Substituting Equation 1 into Equation 2, we get:

2y + 20 = 1.5(y + 20)

Expanding the equation, we have:

2y + 20 = 1.5y + 30

Subtracting 1.5y from both sides, we get:

0.5y + 20 = 30

Subtracting 20 from both sides, we have:

0.5y = 10

Dividing by 0.5, we find:

y = 20

Using this value of y in Equation 1, we can determine x:

x = 2y

x = 2 * 20

x = 40

Therefore, you are currently 40 years old, and your brother is 20 years old.
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We can start by finding out how old you are now. Since you are twice as old as your brother, that means your brother is half your age. So, if you are x years old, your brother is x/2 years old.

Now, we know that in 20 years, you will be 1.5 times your brother’s age. So, you will be x + 20, and your brother will be x/2 + 20.

We can set up an equation based on this information:

x + 20 = 1.5(x/2 + 20)

Simplifying the equation:

x + 20 = 1.5x/2 + 30

Solving for x:

x = 40

So, you are currently 40 years old, and your brother is 20 years old
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Let your brother's current age be B and yours be 2B. In 20 years, your age will be (2B + 20), and your brother's age will be (B + 20). The given condition is 2B + 20 = 1.5 * (B + 20). Solving this equation reveals your brother is currently 20, and you are 40.
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Let's break it down:

Let $$x$$ represent the current age of the brother.

Then, the current age of the person is $$2x$$.

In 20 years, the age of the brother will be $$x + 20$$, and the age of the person will be $$2x + 20$$.

According to the second statement:

$2x + 20 = 1.5(x + 20)$

Now, let's solve for $$x$$:

$2x + 20 = 1.5x + 30$

$0.5x = 10$

$x = 20$

So, the brother is currently $$20$$ years old, and the person is $$2 \times 20 = 40$$ years old.